Vraj Rao - Mr. Z. Syed - SCH4U Grade 12 Chemistry
Unit 1:
Structures and Properties of Matter
History of the Atom
Empedocles
Proposed that Matter was made of 4 elements (fire, air, earth, water)
Democretes
Thought experiment
"What would happen if matter could be cut in half an infinite number of times?"
After each cut, the identity would be unchanged
Eventually reach a piece that cannot be cut
Atomos
Lavosier
Law of Conservation of Mass
Mass is neither created or destroyed, only conserved
Proost
Law of Definite Proportions
Different samples of any pure compound contain the same elements in the same proportions by mass
Dalton
Law of Multiple Proportions
The masses of one element that can combine chemically with a fixed mass of another element are in a ratio of small wholes
Atomic Theory
Matter is composed of indivisible particles
All atoms of a particular element are identical
Different elements have different atoms
Subatomic Particles
Electrons
1897 by J.J. Thomson
While working with cathode rays
Observed how they rays were bent by magnets, and how it could help estimate the mass of the rays
Concluded that the rays were in fact small negatively charged particles - called them Corpuscles (we now call them electrons)
Went on the propose the Plum Pudding Model
Protons
Rutherford adjusted his experiment
Bombarded "N" atoms, and noticed that Hydrogen ions were released
Concluded that Hydrogen ions are fundamental particles - called them Protons
Light
Light
A type of electromagnetic radiation (ER)
Carries energy through space
Many types of ER in addition to visible light
Electromagnetic Spectrum
Shows the types of ER arranged in order of decreasing wavelength
Wavelength and Frequency
Pattern of peaks and troughs
Peak: Top of pattern
Trough: Botom of pattern
Frequency: The number of cycles (WL) per second that passes a given point
Terminology
Refraction
Whenever light goes from 1 medum to another, at an angle, the angle changes, making the light beam beng
Dispersion
The amount of bending that occurs depends on WL of light
As WL increases, bending decreases
Planck's Constant
Matter absorbed/emitted energy in whole number multiples of hv
Shows that energy can only be transferred in "packets" AKA quantum (plural is quanta)
Photoelectric Effect
1887 by Heinrich Hertz
Certain metallic surfaces lose their negative charges when exposed to light/electricity (not the light's intensity)
Frequency of light determines how quickly the metal would lose its charge
Einstein later explained
Light itself consists of individual quantum particles, called Photons
Compton Effect
Loss of frequency from shattered X-ray suggests that X-rays have momentum, because light can have properties and behave like Matter
Emission Spectrum
1880s by J.J. Balmer
Specific WL given off by the light of atoms
WL = B (n^2/n^2-m^2)
WL = wavelength of the light emitted
B = Balmer constant for Hydrogen = 364.50682 m
n = integer such that n>m
m = 2
Atoms
Bohr Model
Electrons orbit the nucleus at certain discrete distances
Orbits have defined energies called shells/levels
Energy of shells increase as one proceeds away from the nucleus. Electrons only gain/lose energy by jumping from an allowed orbit to another
Specific quantities of energy/light are required for an electron to "jump" to a higher orbit - AKA - specific elements absorb specific quantities for energy/light
Emission Spectrum = Absorption Spectrum
Energy released when an electron falls from level 4 to 1 is the same amount of energy required for an electron to jump from level 1 to 4
delta Ejump = delta Efall
Binding Energy
Rydberg's Constant (Rh) = 2,18^10^-18 J
E = Rh/n^2
Structures
Lewis Dot Diagrams
Write the chemical name of the substance and draw its valence electrons around it in a circle. Keep in mind the sharing of electron pairs in compounds
VSEPR
Steps
#1. Draw Lewis-Dot-Diagram for the molecule and count the number of electron charge clouds surrounding the atom
#2. Identify the charge clouds as bonding electrons or as lone pairs
#3. Use VSEPR Notation to determine the molecule's shape
AXmEn
A = Central atom
X = Bonding set
m = Number of bonding sets
E = Lone pairs
n = Number of lone pairs
Molecular Shape and Polarity
Bonds
Types
Ionic
Polar Covalent
Non-Polar Covalent
A molecule may have polar bonds but may not be polar
Use electronegativity to predict the polarity of each bond
Steps
#1. Draw the Lewis structure
#2. Draw VSEPR diagram based on Lewis structure
#3. Add electronegativity of the atoms and assign (lamda+) and (lamda-) to the bonds
#4. Draw in teh bond dipoles
Polarity
When 2 atoms bond
Sharing of a pair of electrons can be polar, non-polar, or ionic
When bonding is polar
a bond dipole is created
The more EN atom has a partial negative charge
The less EN atom has a partial positive charge
Forces
Intramolecular
Forces excerted within a molecule/polyatomic ion
Intermolecular
Forces exerted between molecules/polyatomic ions
Influence physical properties of substances
Forces of attraction/repulsion between molecules
4 Categories
Dipole-Dipole
Attraction between opposite partial charges of polar molecules
Polar molecules are more attracted to each other than similar N-P molecules
Contribute to higher melting/boiling points in polar molecules
Ion-Dipole
Attraction between partial charges of polar molecules/ions
Can occur between
Polar molecule (negative end) and cation
Cations usually smaller than anions
Polar molecule (positive end) and anion
Dipole-Induced Dipole
Electrons in atoms are in constant motion
Possible to induce formation of dipoles in NP molecules
Attraction between a polar molecule and a temp. dipole of a NP molecule
Attraction between an ion and a temp. dipole of a NP molecule
Dispersion
Weak attraction between all molecules
Occurs because NP molecules spontaneously form temp. dipoles
Strongest to Weakest
#1. Hydrogen bonding
#2. Dipole-Dipole interactions
#3. Ion-Dipole interactions
#4. Dipole-Induced Dipole interactions
#5. Dispersion forces
Hybridization
Valence Bond Theory
Covalent bond formation and molecular shapes based on orbital overlap
Molecular Orbital Theory
Covalent bond formation and molecular shapes based on the formation of new molecular orbitals
Principals
#1. Region of orbital overlap has a MAX of 2 electrons
#2. Should be MAX orbital overlap
#3. Concept of atomic orbital hybridization is used
Types
Single Bond
Involves 1 SIGMA bond
Double Bond
Involves 1 SIGMA bond and other PI bonds
Triple Bond
Involves 1 SIGMA and 2 PI bonds
sp = Linear
sp^2 = Trig. Planar
sp^3 = Tetrahedral
sp^3d = Trig. Bypyram.
sp^3d^2 = Octahedral
ETC
Number of hybrid orbitals that form = Number of atomic orbitals that combined to make the hybrid orbitals
Unit 2:
Organic Chemistry
Organic Molecules
Naming Hydrocarbons
Components of Names:
Root: The number of Carbons in
the largest chain
Root Names:
*insert pic*
Suffix: The functional group
Suffix Names:
*insert pic*
Basic Naming Rules
#1. Identify the suffix
#2. Identify the root (longest continuous
chain of Carbons)
#3. Assign numbers (locants) to the principal functional
group as lowest common chain
Functional Groups
Types
Alkanes (-ANE)
Hydrocarbons with single bonds
Steps
#1. Find the longest C chain and number them appropriately in ascending order (find the correct name from the chart)
#2. Find all the substituents and name them correctly from the chart
#3. Identify which numbers of substituents are connected to the C chain
Other "Add-ons"
Cycloalkane
Ring like structure of alkanes
Haloalkanes
Alkanes with halogen atoms
Structural Isomers
Compounds with the same molecular formula but with different bonding arrangements
Aromatic Hydrocarbons
Contain a benzene ring as a base
ORTHO
O-
META
M-
PARA
P-
Alkenes (-ENE)
Hydrocarbons with double bonds
Steps
#1. Root name = longest continuous C chain, with double bonds
#2. Insert the number for where the double bond is located
#3. Suffix family
lowest numbers are Priority
Where there's more than 1 double bond, add "a" to the end of the prefix (e.g. meth=metha)
Other "Add-ons"
Cis-
If the 2 alkyl groups, C, of the parent chain are on the SAME side of C=C
Longest C chain forms U shape
Trans-
If the 2 alkyl groups, C, of the parent chain are on the OPPOSITE side of C=C
Longest C chain forms Z shape
Alkynes (-YNE)
Hydrocarbons with triple bonds
Steps
#1. Number of C in longest chain
#2. Location number
#3. Suffix family
Diagrams
Structural diagram
Similar to Lewis diagrams
Condensed diagram
Understood as carbons are beside carbons (short forms used)
Line diagram
Vertex of each line is a carbon, Hydrogens not mentioned
General "in-case" Rules
Alphabetical order
First Point of Difference
Organic Reactions
Substitution
An "H" atom(s) are substituted by a different atom(s)
C-C bonds in Alkanes are difficult to break
Usually "H" replaced by a Halogen atom
Addition
Alkenes & Alkynes have a greater tendency to undergo this reaction
Hydrogen, Halogens, Hydrogen Halides, and Water can be added
Markovnikov's Rule
The rich get richer
Elimination
The reverse of an Addition reaction (double bond is usually formed)
Common place amongst alcohols and alkyl halides
Zaintsey's Rule
The poor get poorer
Alcohols and Related Reactions
Alcohol
Contains the hydroxyl group (-OH)
Can be prepared by adding Water to an Alkane
Steps
#1. Root name based on longest C chain with -OH attached
#2. Chain is numbered so as to give the alcohol unit the L.P.N.
#3. Alcohol suffix comes after the Hydrocarbon suffix, minus the "e"
E.G. Methene + -ol = Methanol
Classifications - according to the type of Carbon to which the "-OH" group is attached
Primary (1)
Secondary (2)
Tertiary (3)
Phenol
When benzene contains 1 single hydroxyl group the common name is used as its UIPAC name
Aldehydes
Carbonyl group is attached to the end C
Steps
#1. Take the longest chain containing the Carbonyl group
#2. Remove the "e" and add "al" as the ending
#3. This carbonyl group is assigned as C-1
#4. Branches are named as per usual rules
Ketones
Carbonyl group is attached to a C that is not at the end
Steps
#1. Take the longest chain containing the Carbonyl group
#2. Remove the "e" and add the "one" as the ending
#3. Indicate the position of the Carbonyl using the L.P.N. coefficient
#4. Any substituents are named as per usual rules
Esters
Made by joining an Alcohol and a Carboxylic Acid - 2 parts, 1 comes from each
Steps
#1. Convert the suffix "(a)nol" ending of the alcohol to "yl"
#2. Convert the "oic acid" ending of the carboxylic acid to "oate"
Amides and Amines
Organic compounds that contain "N"
Amine
Steps
#1. Identify the largest Alkyl group attached to the "N" atom as the parent Alkane
#2. Replace the "-e" at the end of the Parent Alkane with "-amine"
#3. Include the position number if required
Amide
Steps
#1. Locate the part of theAmine that contains the C=O group and name the Parent Carboxylic acid that this part derives from
Keep in mind, the C=O group is ALWAYS given the number 1 position
#2. Replace the "-oic acid" ending of the Parent acid with "-amide"
Ethers
Formed by Condensation reaction, when 2 alcohol molecules react
2 Alkyl groups (the same or different) attached to an "O" atom
Steps
#1. Identify the longest Alkyl group as the Parent alkane
#2. Give the longest Alkyl group an appropriate hydrocarbon name
Include any branches / other functional groups as necessary
#3. Consider the smaller hydrocarbon group to be a branch that contains "O"
Add "oxy" to the root
#4. Join the "oxy" branch to the larger Hydrocarbon group
Listed in alphabetical order
Unit 3:
Energy Changes and Rates of Reaction
Thermodynamics
Definition & Importance
Understanding heat transfer properties is important
for building sufficient materials
All chemical reactions result in Heat Transfer
Different types of matter require different amount of
Heat Transfer to change the same temperature
Water is unusual - it can absorb/release a lot of
hear without the temperature drastically changing
Changes in a System
Endothermic Reaction
If the system absorbs energy and the
surroundings lose energy
Exothermic Reaction
If the system releases energy and the
surroundings gain energy
Calorimetry
The measure of heat change due to
a chemical reaction
A calorimeter is used to perform this task, while
a Bomb Calorimeter is a high tech version of this
Important Terms
Heat
The transfer of energy due to contact
Temperature
The measure of internal energy of an object
due to particle motion (kinetic energy)
First Law of Thermodynamics
The total amount of energy in the
universe is constant
Energy cannot be created or destroyed
Calculations
Specific Heat Capacity (c)
The amount of heat transfer required to
change the temperature of 1 gram of a substance
by 1 degree Celsius/Kelvin
c = specific heat capacity (in Joules/Grams*Celsius)
q = quantity of heat transferred (in Joules)
m = mass (in grams)
delta T = temperature (in degrees Celsius)
c = q/mT
q=mcT
Heat Capacity
The amount of heat transfer required to
raise the temperature of a sample by 1 degree
Celsius/Kelvin
c = heat capacity (in Joules/Celsius)
q = quantity of heat transferred (in Joules)
delta T = temperature (in degrees Celsius)
c = q/T
q= cT
Enthalpy
Total kinetic and potential energy of a
system at a constant pressure
Molar Enthalpy
The change in enthalpy on a per-mole basis
Enthalpy of Formation (delta Hf)
The amount of heat absorbed/released when 1 mole of the substance is formed at standard temperature (25 degrees Celsius) from its elements in their standard states
The (delta Hf) for elements in their standard states are ZERO
delta H = sum of (delta Hf of products) - sum of (delta Hf of reactants)
Hess's Law of Summation
The "H" is the same as the sum of the values
of the "H" for each individual step
Rules
#1. If all the coefficients of an equation are multiplied/ divided by a common factor, the "H" must be changed likewise
#2. When a reaction is reversed, the sign of "H" must also be reversed
#3. When cancelling compounds for Hess's Law, the state of the compounds is really important
Steps
#1. Number each given thermochemical equation
#2. Arrange the equations so that your desired reactants are on the LEFT side and the products are on the RIGHT side
#3. Multiply the equations by factors such that they match the desired equation (multiply the enthalpies by the same factor)
#4. Add the equations and enthalpies together (cancel out any repeating chemicals)
Reaction Rates
Rate of Reaction
How quickly reactants disappear to form products
Chemical reactions indicate the overall changes that is observed
Rate Theories
Collisions
Transition State
Catalysts
Reactions that require a GREATER number of particles to collide at the same time will DECREASE the chances of a successful reaction to occur
Factors Affecting Reaction Rates
#1. Chemical Nature
Precious metals are discovered first
Not very reactive
Alkali metals later founds (first found only in compounds)
Due to high reactivity
#2. Surface Area
Increase in surface area = Increase in the reaction rate
Heterogenous Reaction
The reactants are in different phases/states
Homogeneous Reaction
All the reactants are in the same phase/state
#3. Concentration
Higher the concentration = Higher the reaction rate
More chemicals result in more particles which can participate in the reaction
#4. Temperature
Higher the temperature = Higher the reaction rate
Increased temperature is due to increased particle motion
Greater the motion of a particle, the greater the chance it will encounter another reactant
#5. Catalyst
A compound that increases the rate of a chemical reaction without being consumed in the actual reaction
It lowers the amount of required energy for the reaction to occur
Also known as Activation Energy
Calculations
Rate Equation
rate = delta concentration / delta time
rate = K {A}^x {B}^y
Rate is measured in moles per litre per second (mol/L*s)
In the sense where A+B = C + D
The x and y values are determined by the actual experiment
K = the rate constant, determined by the reaction and the conditions the experiment was conducted in
Exponents of the Rate Law are NOT related to the coefficients, of the balanced chemical equation in any way
Rate Law Exponents
Exponents are related to the "Order of the Reaction"
Order of the Reaction
Experimentally determined by changing 1 reactant at a time and looking at how the reaction rate changes
The sum of the rate law exponents
Overall order = m
Unit of K = L ^(m-1) / mol ^(m-1) *s
Reaction Mechanisms
Occur over a set of stpes
Each step of the mechanism is known as "Elementary Process"
The overall reaction can only be as fast as the slowest elementary process (AKA Rate-Determining-Step)
Predicting Mechanisms
Only best guesses at the behaviour of molecules
Steps
#1. Each step must be elementary
Involve no more than 3 reactant molecules
#2. The slowest step (Rate-Determining-Step) must be consistent with the rate equation
#3. All the elementary steps must add up to the overall equation
Unit 5:
Electrochemistry
Net Ionic Equations
Any aqueous compounds completely ionize in water
Solids, liquids, or gases do NOT dissociate (completely ionize) in water
Steps
#1. Chemical equation
Normal equation written in the chemical names
#2. Turn the chemical equation into an Ionic equation
All the aqueous are separated into its component ions
#3. Complete the Net Ionic Equation
All the spectator ions (those which are the same on both sides of the equation) cancel out, and the final equation is written from the remaining components
At the end, the equation can be confirmed by counting all the atoms and charges on each side and making sure they are balanced
Oxidation and Reduction
Historical Definitions
Oxidation
Reaction of substances with oxygen (combustion OR corrosion)
Reduction
From metallurgy - producing metals from their compounds
Modern Definitions
Oxidation
The atom/ion that LOSES electrons
Reduction
The atom/ion that GAINS electrons
LEO the lion says GER
Loss of Electrons - Oxidation
Gain of Electrons - Reduction
Both reactions happen SIMULTANEOUSLY - referred to as REDOX reactions
Agents: One reactant causing a change in the other reactant
Oxidizing Agent
The reactant which causes the other to be OXIDIZED
Therefore, this reactant is reduced
Reducing Agent
The reactant which causes the other to be REDUCED
Therefore, this reactant is OXIDIZED
Half-Reactions
To monitor the transfer of electrons, represent each reaction seperately
A balanced chemical equation that shows the number of electrons involved
Oxidation Numbers
Used to keep track of electrons during reactions
An arbitrary system based on charge of ions and EN
Rules
#1. A pure element has an Ox. Number of ZERO
#2. The Ox. Number of an element in a monotomic ion equals the charge of the ion
#3. The Ox. Number of Hydrogen in its compounds is +1 except in metal hydrides, where the Ox. Number of Hydrogen is -1
#4. The Ox. Number of Oxygen in its compounds is usually -2, but there are certain exceptions
#5. In covalent compounds that do not contain "H" or "O" the more EN element is assigned an Ox. Number that equals the negative charge it usually has in its ionic compounds
#6. The sum of the Ox. Numbers of all the elements in a compound is ZERO
#7. The sum of all the Ox. Numbers of all the elements in a polyatomic ion equals the charge on the ion
Steps
#1. Assign common Ox. Numbers
Use the Periodic Table of Elements
#2. The total Ox. Numbers of a molecule/ion is the value of the charge of the molecule/ion
For neutral compounds, the Ox. Number of all the atoms must add up to ZERO
#3. The unknown Ox. Numbers can be assigned algebraically and be solved using variables
Unit 4:
Chemical Systems and Equilibrium
Equilibrium
Occurs when opposing changes (FWD and RVS reactions) are occurring simultaneously at the same rate
Theoretically, all reactions are reversible
Reactions wrtiten L-R are FWD reactions
Reactions written R-L are RVS reactions
Represented by an "equal sign" which has an arrow
pointing the opposite direction on each line
Both reactions occur until the concentrations of
reactants AND products undergo no further change
Keep in Mind
The reactant and product concentrations are CONSTANT, not equal
FWD reactions occur rapidly during the start, then slows down as reactant concentrations decrease
RVS reactions occur slowly during the start, then speed up as product concentrations increase
Generally, an equilibrium is a state of balance
EQLBM constant K
Dependence
Doesn't depend on the Reaction Mechanism
Doesn't depend on the initial concentrations
Depends on Temperature
Depends on the EQLBM concentrations
Magnitude
Since products are divided by reactants in the expression:
A larger K value (>1)
FWD reaction is favoured
A smaller K value (<1)
RVS reaction is favoured
All substances present are being made and unmade at the same rate
The Reactants are ALWAYS on the LEFT, and the Products are ALWAYS on the RIGHT side of an equation
At a given temperature, the reactants and products with ALWYAS be in the SAME RATIO at EQLBM, no matter the starting point
Le Chatelier's Principle
When a system at EQLBM is stressed, the syste, works to restore EQLBM once again
Types of Stress
Changes in Concentration
System shifts to get back to the same ratio of reactants and products
Means that Keq is constant
Changes to the Temperature
When temperature is increased, Endothermic reactions are favoured
Consider HEAT as a Reactant in Endothermic Reactions
A + B + Heat = AB
If heat is added
Shift to Products side
If heat is removed
Shift to Reactants side
When temperature is decreased, Exothermic reactions are favoured
Consider HEAT as a Product in Exothermic Reactions
A + B = AB + Heat
If heat is added
Shifts to Reactants side
If heat is removed
Shifts to Products side
Changes to the Pressure
Only affects EQLBM systems with unequal moles of Gaseous reactants and products
States of Equilibrium
Static
One in which there is NO motion
Dynamic
One in which there is motion, despite there being no Net Change
Chemical (an example of Dynamic)
The state where the reaction vessel contains a
mixture of all the reactants and products
Different Systems
Homogeneous
An EQLBM system in which all the components are in the SAME physical state (e.g. gas, aqueous, solid, liquid)
Heterogeneous
An EQLBM system in which the components are in DIFFERENT physical states (e.g. gas, aqueous, solid, liquid)
Calculations
Concentration
{C} = solute / solution
EQLBM Constant Expression
AKA Law of Chemical EQLBM , AKA Law of Mass Action
K = {products} / {reactants}
let the EQLBM sign be represented as {=}
E.G. aA + bB {=} cC + dD
K = {C}^c + {D}^d / {A}^a + {B}^b
Steps
#1. Calculate the molar concentrations
#2. Write the EQLBM expression
#3. Substitute the respective values and solve
Changes in Substances
Adding reactants
Shift to products side
Rf > Rr
Removing reactants
Shift to reactants side
Rf < Rr
Adding products
Shift to reactants side
Removing products
Shift to products side
RICE Table
R = Reaction
I = Initial Amounts (in concentration)
C = Change = Use variables
E = EQLBM value = Initial Amount - Change Variable
Solved using Keq = {products} / {reactants}
Acids and Bases
FIRST
Arrhenius Theory
Acid
pH level below 7
A substance that contains HYDROGEN in its chemical formula
Ionizes in water to form HYDRONIUM ION
Base
pH level above 7
A substance that contains HYDROXIDE ION (OH-) in its chemical formula
NEW
Bronsted-Lowry Theory
Acid
A proton DONOR
Base
A proton Acceptor
Conjugate
Acid-Base Pair
A pair of 2 substances related by the gain/loss of protons
Conjugate Acid
The particle formed after a proton JOINS a BASE
Conjugate Base
The particle remaining after a proton LEAVES an ACID
Strong vs Weak
Acid
Strong
An acid that COMPLETELY dissociates into ions in water
Weak
An acid that has LIMITED dissociation in water
The conjugate acid of a Strong Base is a weak acid
Base
Strong
A base that COMPLETELY dissociates into ions in water
Weak
A base that has LIMITED dissociation in water
The conjugate base of a Strong Acid is a weak base
Percent Dissociation
Ratio of concentration comparing ionized acid/base at EQLBM to original concentration of acid/base
Steps
#1. Calculate the concentration using pH
#2. Setup the RICE table and add values
#3. Create and solve teh EQLBM expression
#4. Calculate the Percent Dissociation
% Dissociated = ( {}dissociated / {}initial ) *100%
Kw = (Ka)*(Kb)
Can be re-arranged to solve for missing K_ value
Ka = Acid-Dissociation Constant for the Ionization of an Acid
Ka > Kb = solution is Acidic
Kb = Base-Dissociation Constant for the Ionization of a Base
Ka < Kb = solution is Basic
Final Concentration Calculations
Steps
#1. Determine the MOLES of both, acid and base
#2. Find the difference between the two values and determin which one has excess
#3. Re-calculate the concentration of the acid/base using the excess moles and the combined volume
Miscellaneous
Amphiprotic Substances
A molecule/ion which can accept/donate a proton
Can act as an acid or a base
Titrations
A-B Titration Curve
A graph of pH of an acid/base solution vs Amount of ADDED acid/base
Equivalence Point
The point in a Titration where the amount of Acid present exactly equals and reacts with amount of Base present
Steps
#1. Calculate the moles of Acid/Base
#2. Determine the excess moles and new concentration
#3. Use Kw to calculate the concentration and find pH
Solubility (Qsp)
Molar Solubility
The amount (in moles) of solution in 1L of saturated solution
Precipitate
An insoluble product that forms from a reaction between 2 soluble ionic compounds