Divisor de voltaje en AC
Encuentre ZT
ZT= 3*10^3+(2*10^3i-110^3)-3*10^3+1*10^3i
α= tan^-1(4*10^3/3*10^3) = 18.43°
f= w/2π = 314/2π = 49.87°
Xc= -i/ 2πcf = 1*10^-3i = -i/2πc*49.97
C= -i/ 2π(-1*10^3i)(49.87)= 3.185*10^-6F
XL= L(2πfi)= L = XL/2πfi = 6.37Hz
e = 6sen(314t + 60°)
E= 6/√2=4.24<60°
I= E/2T = 1*10^-3+0.889*10^-3
i = 1.34*10^-3<41.63°
Encontrar VR, VL y VC
VR=(1*10^3+0.889*10^3)(3*10^3)
VR= 3+2.66i = 4.014<41.56°
VL=(1*10^3+0.889*10^-3i)(2*10^3)
VL= -1.778+2i = 2.67<48.36°
VC= (1*10^3+0.889*10^-3i)(-1*10^3I)
VC= 0.889i = 1.338<48.36°