by 2021AS Cipolla Miriana Antonia 3 years ago
246
More like this
-
+
am=a x a x...
a:b=(a:c):(b:c)
a:b=(axc):(bxc)
axb=0--->a=0 o b=0
ELEMENTO NEUTRO 1
DISTRIBUTIVA
ax(b+c)=(axb)+(axc)
(a+b)xc=(axb)+(bxc)
(axb)xc=ax(bxc)
axb=bxa
INVARIANTIVA
(a-b)=(a-c)-(b-c)
(a-b)=(a+c)-b+c
ELEMENTO NEUTRO 0
a+(-a)=0
ASSOCIATIVA
(a+b)+c=a+(b+c)
COMMUTATIVA
a+b=b+a