by Fuad Jahen 13 years ago
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Suppose P(x) is a polynomial function with integer coefficients and x= b/a is a zero of P(x), where a and b are integer and a≠0. Then, b is a factor of the constant term of P(x) a is a factor of the leading coefficient of P(x) ax-b is a factor of P(x) Example: Consider a factorable polynomial such as P(x) = 3x² + 7x – 2. Since the leading coefficient is 3, one of the factors must be of the form (3x-b), where b is a factor of the constant term 2 and P(b/3) = 0 To determine the values of x that should be tested to find b, the integral zero theorem is extended to include polynomials with leading coefficients that are not one.
If (x-b) is a factor of a polynomial function P(x) with leading coefficient 1 and remaining coefficients that are integers, then b is a factor of the constant term of P(x). Example: Consider the polynomial P(x) = x² + 6x – 5 A value that satisfies P(b) = 0 also satisfies b² + 6b – 5 =0, or b² + 6b = 5. Since the product of b² + 6b – 5 is 5, the possible integer values for the factors in the product are the factors of 5. They are ±1,±5.
Corresponding Statement
Quotient Form
LONG DIVISION FORM
Q(x) = Quotient
P(x) = Polynomial equation/ Dividend
R = Remainder
(x-b) = Divisor/Binomial equation