Final Revisionnn

Mehr dazu

Questionm 4: Alternatives to Custody and IAC's

von Gillian Dickinson

MAP ISRAEL

von Carolina Rozo Poveda

Easter 2012

von Daniel Sima

Pets

von Justin Blessinger

Final Revisionnn

Coasts

Blackwater Estuary

Soft Engineering techniques

Hurricane Katrina

Features of Beaches

Sub-aerial weathering

Tides

Rivers

Hard and Soft engineering techniques

Hard Engineering

Diversion Spillways

Channel Straightening

Levees

Dams

Hydroelectric Power

Make Resoviors

Huge Walls

Formation of Meanders

7. Oxbow Lakes

6. Bends become exaggerated giving asymmetric cross profiles

5. Causes helicoidal flow => erosion and deeper pools deposition

4. Turbulence increase in pools

3. Uneven river flow across cross section

2. Higher efficiency in pools => more energy

1. Alternating riffles and pools

Upper, Middle and Lower sections

Lower Section

Lateral erosion in meander formation

Clay, sand, silt

Suspension Solution

Middle Section

Sand and gravel

Lateral Abrasion Attrition

Saltation Most Suspension

Upper Section

Deposition

Little, largest

Transportation

Large Traction Saltation

Erosion

Vertical Abrasion Hydraulic Action

Food Supply Issues

Intervention Pricing

Non-Market Policies

Increasing Food Production

Sustainability

TNCs

Population

Wards of Herefordshire

French pro natalists

Chinese One Child Policy

Malthus, Boserup, Club of Rome

Youthful and Ageing populations

C1

Proof of arithmatic series:

Sum of terms Sn= (a)+(a+d)+(a+2d)...+(a+(n-2)d)+(a+(n-1)d) Flip it over Sn=(a+(n-1)d)+(a+(n-2)d)...+(a+2d)+(a+d)+(a) Add together 2Sn=(2a+(n-1)d)+(2a+(n-1)d)... n number of (2a+(n-1)d) therefore 2Sn= n(2a+(n-1)d) Sn= 1/2 n (2a+(n-1)d)