Kategoriak: All - inverse - growth - matrices - stability

arabera Vũ Lâm 11 years ago

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Vu Lam's math map

The content focuses on several topics in linear algebra and differential equations. It begins with the basics of matrices, including the concepts of transpose, square matrices, and elementary row operations.

Vu Lam's math map

Vu Lam's math map

Linear transformation

let C in R

let u =(u1,u2) in V

let v =(v1,v2) in V

1) show cT(u) = T(cu)

2)show T(u+v) = T(u) +T(v)

if they are the same -> linear transformation

general solution
not enough lamda

find u

x = C1e^lamdatv +C2te^lamdatv + C2e^lamdatu

repeated lamda

x = C1e^lamdatv1 +C2te^lamdatv2

x = C1e^lamda1tv1 +C2e^lamda2tv2
eigen value & eigen vector
find eigen vector

plug lamda back to |A-lamda*I|=0

find eigen value

|A-lamda*I|=0

T(v) = lamda(v)

v =eigen vetor

lamda = eigen value

Ker(T)
Nullity

how many vector is in ker(T)

if it = 0, injective

Ref of A

write as system equation and parameter equation.

colA
REF of A

according to leading 1 of REF, refer to the original matrix a. those vector are the bases of col(A)

if it = codomain, surjective

rank

n-the nunber of non pivot colum if A

the nbuber of pivot column in A

dim(im(T)) = dim(colA)

Matrices

A^T : transpose of A: interchange the row and column vector in an m x n matrix A

square matrix: same member of m x n

main diagros { 1 0 0

0 1 0

0 0 1}

tr(A): trace of A: sum main diaro

Subspace
let u in W where u = (u1,u2,u3) let v in w where v = (v1,v2,v3) let Cin R

if those are equal, hence closed with respect to scalar multiplication W in a subspace of V

show CU in W

show u+v in W

Inverse of matrix A = A^-1
Invertible: detA not equal 0 not Invertible: detA = 0
[A|I] = [I|A^-1]

A^-1 = 1/det [W - y -Z x]

only work for 2 x 2 matrix

x = A^-1*b
inconsistance: no solution
consistance: have solution or infinite solution
Independent variable: free variable
dependent variable: bound variable
pivot column: column contain leading 1
RREF

1) its a row echelon matrix

2) any column that contain a leading 1 has 0 everywher else

elementary row operation

ERO

1) trade rows places (permit): change row

2) multiply every element in row by no zero scalar

3) add element of 1 row to correspinding element of another row

Laplace transforms

Unit step function
solve for y(t) by using the table
write step function for it
draw the pic from given information
use the laplace table
F(s) = interal e^-st f(t) dt from 0 to infinity

Second order DE

Using laplace transforms
L[f^n] = s^n L[f] - s^(n-1) f(0) - s^(n-2)f'(0) ... - sf^(n-2)(0)-f^(n-1)(0)
Undertermined coefficent
ay'' +by' +cy = f(t)

y = yh +yp

yp

f(t) is trig family

yp = Asint+Bcost y'p=Acost - Bsint y''p=-Asint-Bcost solve for A and B

f(t) is exp family

yp = Ae^t y'p=Ae^t y''p=Ae^t solve for A

if serpent bite: yp = Ate^t

if bite twice: yp = At^2e^t

f(t) is poly family

yp = At^2 + Bt + C y'p = 2At + B y''p =2A solve for A, B, C

yh =homogenous

using characteristic equation to sove for

electric circuits: LQ'' + RQ' + 1/CQ =V(t)
ay'' + by' +cy = 0
Simple harmonic oscillator: mx'' + bx' + kx =f(t)
use characteristic equation: ar^2 + br + c = 0

solve for discriminante : delta = b^2 - 4ac

if delta<0: y(t) = e^at(c1cos(bt)+c2sin(bt))

if delta=0: y(t) = c1e^rt + c2te^rt

if delta > 0: y(t) = c1e^r1t + c2e^r2t

First order DE of the form

System of differential equations
dx/dt = P(x,y) dy/dt = Q(x,y)

graph those. choose vnull point plug into hnull. if it <0, down arrow. choose Hnull point plug into vnull. if it < 0, left arrow.

set dy/dt = 0,solve for y : H null

set dx/dt = 0, solve for y: V null

system in 2 variables

first order

autonomous: no t involve

mixing and cooling
Newton's law of cooling

dT/dt = k(M-T)

T(t) = Toe^-kt + M(1-e^-kt)

temperature of the object

M is the medium temp

K is the constant of propotionality

dx/dt = rate in - rate out

rate out = (concentrate out) * (flow rate out)

rate in = (concentrate In) * (flow rate in)

Growth and decay
dA/dt = rA+d

A(t) = Aoe^rt + d/r(e^rt - 1)

d is the additional dollars per year from the depositor

r is interest rate compound continously

A(0) = Ao

dy/dt = Ky

y=yoe^kt

y(to) = yo

K<0, k is decay factor

K>0 , k is growth factor

Using Laplace transforms
L[f']=sL[f] - f(0) =sF(s) - f(0)
Intergrating factor
dy/dt + p(t)y = f(t)

intergrate both side respect to t

multiply both side by u(t)

u(t)=e^interal(p(t)dt

Intergrating directly
dy/dt = f(t)

If having IVP, find the value

intergrate both side

Separable equation
dy/dt = f(t)g(y)

if having IVP, find the value

if possible,solve for y in term of t

Intergrate each side

Now assume g(y) not equal 0, rewrite the equation in saparated or differential form: dy/g(y) = f(t)dt

set g(y) = 0 and solve for equalibrium solution, if any

dy/dt = f(y,t) = slope
Concative change

2nd derivative = 0

Stability

Concave up

Concave down.

Equilibrium

occur at y = k where dy/dt = 0

solution have to remain all the time

Isoclines "equal slopes"

Place where slope is the same

General solution: y = Ce^2t