Categories: All - division - polynomial - roots - rational

by Loraine Flores 7 years ago

299

POLYNOMIAL FUNCTION

Determining the upper and lower bounds of a polynomial function involves using synthetic division to assess the behavior of real roots. The process entails dividing the polynomial by (

POLYNOMIAL FUNCTION

POLYNOMIAL FUNCTION

LEADING COEFFICIENT TEST

IDENTIFY THE LEADING COEFFICIENT
Identify the coefficient of the leading term.
Identify the term containing the highest power of x to find the leading term.
Find the highest power of x to determine the degree.
Each real number aiis called a coefficient. The number that is not multiplied by a variable is called a constant. Each product is a term of a polynomial. The highest power of the variable that occurs in the polynomial is called the degree of a polynomial. The leading term is the term with the highest power, and its coefficient is called the leading coefficient.

UPPER AND LOWER BOUND

Checking the Upper Bound: Note how c = 4 > 0 AND the all of the signs in the bottom row of our synthetic division are positive. You know what that means? 4 is an upper bound for the real roots of this equation. Since - 4 is a lower bound and 4 is an upper bound for the real roots of the equation, then that means all real roots of the equation lie between - 4 and 4.
Checking the Lower Bound: Lets apply synthetic division with - 4 and see if we get alternating signs:
- 4 is a lower bound for the real roots of this equation.
You know what that means?
Note how c = -4 < 0 AND the successive signs in the bottom row of our synthetic division alternate.
Example 1: Show that all real roots of the equation example 1a lie between - 4 and 4. In other words, we need to show that - 4 is a lower bound and 4 is an upper bound for real roots of the given equation.
Lower Bound If you divide a polynomial function f(x) by (x - c), where c < 0, using synthetic division and this yields alternating signs, then c is a lower bound to the real roots of the equation f(x) = 0. Special note that zeros can be either positive or negative.
Upper Bound If you divide a polynomial function f(x) by (x - c), where c > 0, using synthetic division and this yields all positive numbers, then c is an upper bound to the real roots of the equation f(x) = 0. Note that two things must occur for c to be an upper bound. One is c > 0 or positive. The other is that all the coefficients of the quotient as well as the remainder are positive.

DIVIDING POLYNOMIALS

Step 5: Repeat until done.
Step 4: Add the column created in step 3. Write the sum in the bottom row:
Step 3: Multiply c by the value just written on the bottom row.
Step 2: Bring down the leading coefficient to the bottom row.

RATIONAL ZEROS OF POLYNOMIAL

Example: Find all the rational zeros of P(x) = x 3 -9x + 9 + 2x 4 -19x 2 . 1) P(x) = 2x 4 + x 3 -19x 2 - 9x + 9 2 )Factors of constant term: ±1 , ±3 , ±9 . 3)Factors of leading coefficient: ±1 , ±2 . 4)Possible values of : ± , ± , ± , ± , ± , ± . These can be simplified to: ±1 , ± , ±3 , ± , ±9 , ± . 5)Use synthetic division:
We can use the Rational Zeros Theorem to find all the rational zeros of a polynomial. Here are the steps: 1)Arrange the polynomial in descending order 2)Write down all the factors of the constant term. These are all the possible values of p . 3)Write down all the factors of the leading coefficient. These are all the possible values of q . 4)Write down all the possible values of . Remember that since factors can be negative, and - must both be included. 5)Simplify each value and cross out any duplicates. 6)Use synthetic division to determine the values of for which P() = 0 . These are all the rational roots of P(x) .

The degree of a polynomial is the highest power of x in its expression. Constant (non-zero) polynomials, linear polynomials, quadratics, cubics and quartics are polynomials of degree 0, 1, 2 , 3 and 4 respectively. The function f(x) = 0 is also a polynomial, but we say that its degree is ‘undefined’.

MULTIPLICITY OF A ROOT

The practical upshot is that an even-multiplicity zero makes the graph just barely touch the x-axis, and then turns it back around the way it came. You can see this in the following graphs:
The point of multiplicities with respect to graphing is that any factors that occur an even number of times (that is, any zeroes that occur twice, four times, six times, etc) are squares, so they don't change sign. Squares are always positive. This means that the x-intercept corresponding to an even-multiplicity zero can't cross the x-axis, because the zero can't cause the graph to change sign from positive (above the x-axis) to negative (below the x-axis), or vice versa.
A zero has a "multiplicity", which refers to the number of times that its associated factor appears in the polynomial. For instance, the quadratic (x + 3)(x – 2) has the zeroes x = –3 and x = 2, each occurring once. The eleventh-degree polynomial (x + 3)4(x – 2)7 has the same zeroes as did the quadratic, but in this case, the x = –3 solution has multiplicity 4 because the factor (x + 3) occurs four times (that is, the factor is raised to the fourth power) and the x = 2 solution has multiplicity 7 because the factor (x – 2) occurs seven times.
Root of multiplicity 1 is also called a simple root.

THE TURNING POINTS

The polynomial y=x3 y=x3 has no turning points. It has a horizontal tangent line at (0,0) (0,0) which is not a turning point.

NO TURNING POINT

Subtopic
A turning point of a function is a point where the graph of the function changes from sloping downwards to sloping upwards, or vice versa. So the gradient changes from negative to positive, or from positive to negative. Generally speaking, curves of degree n can have up to (n − 1) turning points.

THE INTERCEPTS

Find the x- and y-intercepts of 25x2 + 4y2 = 9 Using the definitions of the intercepts, I will proceed as follows: x-intercept(s): y = 0 for the x-intercept(s), so: 25x2 + 4y2 = 9 25x2 + 4(0)2 = 9 25x2 + 0 = 9 x2 = 9/25 x = ± ( 3/5 ) Then the x-intercepts are the points ( 3/5, 0) and ( –3/5, 0) y-intercept(s): Copyright © Elizabeth Stapel 1999-2011 All Rights Reserved x = 0 for the y-intercept(s), so: 25x2 + 4y2 = 9 25(0)2 + 4y2 = 9 0 + 4y2 = 9 y2 = 9/4 y = ± ( 3/2 ) Then the y-intercepts are the points (0, 3/2 ) and (0, –3/2 )
an x-intercept is a point on the graph where y is zero, and a y-intercept is a point on the graph where x is zero.
The graphical concept of x- and y-intercepts is pretty simple. The x-intercepts are where the graph crosses the x-axis, and the y-intercepts are where the graph crosses the y-axis. The problems start when we try to deal with intercepts algebraically.

A polynomial function is a function such as a quadratic, a cubic, a quadratic, and so on, involving only non-negative integer powers of x. We can give a general definition of a polynomial, and define its degree.