door DANIEL SHANG 3 jaren geleden
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y = x^2 + 6x + 8
Find factors of 8 that have a sum or difference of 6
8 = 2x4
6 = 2+ 4
Therefore y = (x+2)(x+4)
a = 1
Multiply value a with value c. Find factors of the product that have a sum or difference of value b. With those 2 factors, replace value b. Common factor the 1st 2 terms then the last 2 terms.
y = 4x^2 + 7x + 3
4x3 = 12 7 = 3+4 y = 4x^2 + 3x + 4x + 3 y = x(4x + 3)+ 1(4x+3) therefore factored form is y = (x+1)(4x+3)
y = -2x^2 + 14x - 24
Common factor of 2 (-2 so change signs)
y = -2(x^2 - 7x + 12)
Find factors of 12 that have a sum or difference of -7
12 = (-3)x(-4) -7 = -3-4 Therefore y = -2(x-3)(x-4)
x = -b/2a x = -12/2(-2) x = -12/-4 x = 3
substitude AoS into equation for x to find y-value of vertex
y = -2(3)^2 + 12(3) - 11 y = -2(9) + 36 - 11 y = -18 + 36 - 11 y = 18 - 11 y = 7 Vertex = -2(x-3)^2 + 7