por Justin Charno 1 ano atrás
114
Mais informações
Find Zeros(x1,x2)
Find x coordinate of vertex
(x1+x2) _______ 2
Sub x coordinate of vertex into the equation to find y coordinate of vertex
(h,k) represent (x,y) of vertex
2(x-2)^2+6 V=(2,6)
Min/Max Value
Max Value
Parabola opens down, max value is the y coordinate of vertex
Min Value
Parabola opens up, min value is the y coordinate of the vertex
Shows axis of symmetry
a>0, Parabola opens up
a<0, Parabola opens down
Vertical Stretch
Vertical Compression
Discriminant Formula
b^2-4ac
Nature of Roots
Discriminant <0
2 Distinct Real Roots
Discriminant =0
1 Real Root
Discriminant >0
No Real Roots
Can Show The Perfect Square
Discriminant is a perfect square so you don't need to use Quadratic Formula
a(x-s)(x-t)=0
Make each factor =0 to solve
2(x-6)(x+8)
x+8=0 x=-8
x-6=0 x=6
x=-b±√b^2-4ac ______________ 2a
Perfect Square Trinomial
Difference of Squares
a2-b2=(a+b)(a-b)
a=1
Simple Trinomial Factoring
x^2+6x+8 (x+4)(x+2)
a>1
Complex Trinomial Factoring
ax^22 + rx + sx + c
Use Grouping and Distributive Property to factor
a(x+p)^2+q=0
Isolate x for roots
Plot 6 more points with step pattern
1(a),3(a),5(a)