по Anmol Panchal - Turner Fenton SS (2572) 6 лет назад
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Zeros are where a parabola cross the x-axis. A parabola may have one,two, or no zeros
Subtopic
y = a(x-p)(x-q)
can also be changed into Standard form
y = ax² + bx + c
complete the square if a ≠1
y = 2x² - 16x -1 y = (2x² - 16x) - 1 y = 2(x² - 8x) - 1 y = 2(x²- 8x + 16 - 16) - 1 y = 2(x² - 8x + 16) - 16(2) - 1 y = 2(x - 4)² - 33
The first blue Line, is the standard form when a ≠1. Group the x-terms as shown in the red line. Common factor just the a-value from the x-terms. Divide the coefficient of the middle term by 2, square it, then add and subtract that number inside the brackets. Remove the subtracted term from the brackets. Multiply it by the "a" value you factored out. Factor the brackets as a perfect square trinomial.
complete the square if a=1
y = x² - 6x +4 y = (x² - 6x) +4 y = (x² - 6x + 9 - 9) +4 y = (x²- 6x + 9) - 9 + 4 y = (x-3)² - 5
The first blue Line is the standard form.The next line shows how the x variables are grouped. After grouping the x variables divide the middle coefficient by two, square the result, than add and subtract the number inside the brackets.Remove the subtracted term, from the brackets.Factor the brackets as a perfect square trinomial. Remember to solve whats outside the brackets as well. This is the result of factoring the standard form, which is now the vertex form.
y = a(x-h)² + k
a-value
Transformations
The parabola is stretched
More specific on how much the parabola is being compressed or stretched, use the equation, "1a,3a,5a". Substitute the a-values into the equation, as shown below.
The parabola is compressed
The parabola will face upwards
The parabola will face downwards
Translations, which can be either
y = a(x-h)² + k , the k-value is the horizontal translation
y = a(x-h)² + k , the h-value is the vertical translation
The VERTEX(h,k)